Daily Current Affairs January 14 2023

 

CURRENT AFFAIRS: NATIONAL NEWS

Union Minister Shri Sarbananda Sonowal inaugurates School of Logistics, Waterways and Communication in Agartala:

• The Union Minister of Ports, Shipping & Waterways and Ayush, Shri Sarbananda Sonowal, along with Dr Manik Saha, Chief Minister, Tripura inaugurated the School of Logistics, Waterways and Communication.
• The school will enable the rich pool of talent of the region to become world-class experts in the transportation and logistics sector.
• To unlock the promised economic potential of the Northeast, the school will enable the capacity of human resources along our opulent waterways
• The Centre for Logistics, Communication and Waterways would facilitate in conducting studies/research, training, workshops/seminars for stakeholders like businesses, exporters/importers, Chambers of Commerce and Industries, local entrepreneurs, tourist operators etc.

Aptitude Tips and Tricks on Percentage

 PERCENTAGE

What is Percentage: A fraction with its denominator as ‘100’ is called a percentage. Percentage means per hundred. So it is a fraction of the form 6/100, 37/100, 151/100, and these fractions can be expressed as 6%, 37%, and 151% respectively. By a certain percent, we mean that many hundredths. 

Thus x percent means x hundredths, written as x%.  

To express x% as a fraction:We have, x% = x/100.  

Thus, 20% =20/100 =1/5; 48% =48/100 =12/25, etc.  

To express a/b as a percent:We have, a/b = ((a/b)*100)% 

Thus, ¼ =[(1/4)*100] = 25%; 0.6 =6/10 =3/5 =[(3/5)*100]% =60% 

Why Percentage: Percentage is a concept evolved so that there can be a uniform platform for comparison of various things. (Since each value is taken to a common platform of 100) 

Example: To compare three different students depending on the marks they scored we cannot directly compare their marks until we know the maximum marks for which they took the test. But by calculating percentages they can directly be compared with one another. 

Important Points to Remember: 

a)If the price of a commodity increase by R%, then the reduction in consumption so as not to increase  the expenditure is  

[R / (100+R))*100] % 

b)If the price of the commodity decreases by R%, then the increase in consumption so as to decrease the  expenditure is  

[(R / (100-R)*100] % 

c)If A is R% more than B, then B is less than A by  

[(R/(100+R))*100]% 

1. d) If A is R% less than B, then B is more than A by  

[(R/(100-R))*100]% 

Results on Population: Let the population of the town be P now and suppose it increases at the rate of  R% per annum, then:  

1. Population after n years = P [1+(R/100)]n
2. Population n years ago = P / [1+(R/100)]n

Results on Depreciation: Let the present value of a machine be P. Suppose it depreciates at the rate of R%  per annum. Then,

1. Value of the machine after n years = P [1-(R/100)]n
2. Value of the machine n years ago = P / [1-(R/100)]n